the diagonal of a parallelogram bisect each other
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Yes it is true. I want to you to be more precise with you question.
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Question :-
The Diagonals diagonals of a parallelogram bisect each other.
Solution:-
Given :- ABCD is a parallelogram with the diagonals AC and BD and the diagonals bisect each other at the point of O.
To Prove:- OB = OD & OA = OC
To Proof:- We know that Opposite sides of parallelogram are parallel
- AD || BC ( With the transveral BD )
- ODA = OBC ---(1) ( Alternate Interior Angles)
Also. AD ||BC ( with the transveral AC)
Same as ODA = OBC --(2)( alternate interior Angles)
Now, In ∆ AOD & ∆ BOC
- OAD = OBC ---( From eqn 1)
- AD = CD ---( Opposite sides)
- ODA = OBC ---( From eqn 2)
- ∆AOD ~ ∆ BOC ---(By ASA Angle side angle Congruency Rule)
By CPCT ( Corresponding parts of congruent Triangles)
=> OA = OC & OB = OD
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