The diagonal of a parallelogram is 30 cm in length. Two perpendiculars are drawn on the
diagonal from the opposite vertices are 10 cm and 8 cm. Find the area of the parallelogram.
Answers
Answer:
270 cm²
Step-by-step explanation:
Diagonal divides Let AC be the diagonal
So, AC = 30 cm (base of triangle)
Perpendicular's length = 10 cm and 8 cm (height of triangle)
Area of parallelogram = Sum of areas of both triangles
= 1/2 base * height + 1/2 base * height
= 1/2 base( 8 + 10 )
= 1/2 * 30 (18)
= 15*18
= 270 cm²
I am having a slight doubt that diagonals of a parallelogram divide it into 2 congruent, so the altitudes should not be unequal, they should be equal.
If you get it, then do tell me
Anyways, I have answered your question by the general method, so that's the answer.