the diagonal of a polygon is 35 if what is the side
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The formula to find the number of diagonals = n(n-3)/2, where n = no. of sides of the polygon.
Here n(n-3)/2 = 35, or
n(n-3) = 70
n^2 - 3n - 70 = 0, or
(n-10)(n+7) = 0, lor
n = 10 or -7.
Here n(n-3)/2 = 35, or
n(n-3) = 70
n^2 - 3n - 70 = 0, or
(n-10)(n+7) = 0, lor
n = 10 or -7.
Answered by
0
The formula to find the number of diagonals = n(n-3)/2, where n = no. of sides of the polygon.
Here n(n-3)/2 = 35, or
n(n-3) = 70
n^2 - 3n - 70 = 0, or
(n-10)(n+7) = 0, lor
n = 10 or -7.
Hence the figure has 10 diagonals and is a decagon.
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