Question

The diagonal of a quadrilateral is 15 cm and perpendiculars dropped on it from opposite vertices are 6 cm and 9 cm. Find the area of the quadrilateral.
please give right answer​

Answer 1

Given ABCD is a quadrilateral with AC=20cm and BP=9cm & OD=15cm and BP⊥AC & OD⊥AC

area of ΔABC=

2

1

×AC×BP=

2

1

×20×9=90cm

2

[Area of ΔABC−90cm

2

]

Area of ΔADC=

2

1

×AC×OD=

2

1

×20×15=150cm

2

Area of [ΔADC=150cm

2

]

Area of quadrilateral =area of ΔADC+ area of Δ ABC

=90+150

Area of quadrilateral (ABCD)=240cm

2

Hence area of quadrilateral ABCD is 240cm

2

.