Question

the diagonal of a quadrilateral is 20cm in length and the perpendiculars to it from the opposite vertices are 8.5cm and 11cm.Find the area​

Answer 1

Given ABCD is a quadrilateral with AC=20cm and BP=9cm & OD=15cm and BP⊥AC & OD⊥AC

area of ΔABC=

2

1

×AC×BP=

2

1

×20×9=90cm

2

[Area of ΔABC−90cm

2

]

Area of ΔADC=

2

1

×AC×OD=

2

1

×20×15=150cm

2

Area of [ΔADC=150cm

2

]

Area of quadrilateral =area of ΔADC+ area of Δ ABC

=90+150

Area of quadrilateral (ABCD)=240cm

2

Hence area of quadrilateral ABCD is 240cm

2

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Answer 2

Answer:

this is your answer

Step-by-step explanation:

area =1/2(length of the diagonal) (sum of perpendiculars)

area=1/2(20)(11.5+8.5) square cm

area=1/2(20)(20) square cm

area =200square cm