Question

the diagonal of a quadrilateral is 30 cm in the length and the lengths of perpendiculars to it from the opposite vertices are 8 cm 10 cm find the area of the quadrilateral​

Answer 1

Given :

$\: \: \: \: \: \: \: \: \bullet \: \: \sf Diagonal \: (d) = 30 \: cm \\ \\ \: \: \: \: \: \: \: \: \bullet \: \: \sf Perpendicular \: ( h_1) = 8 \: cm \\ \\ \: \: \: \: \: \: \: \: \bullet \: \: \sf Perpendicular \: ( h_2) = 30 \: cm$

To Find :

$\: \: \: \: \: \: \: \: \bullet \: \sf Area \: of \: quadrilateral$

Solution :

Formula to find area of quadrilateral is

$\large \implies\boxed{ \boxed{\sf Area = \dfrac{1}{2} \times d(h_1 + h_2)}} \\ \\ \implies \sf \frac{1}{2} \times 30(10 + 18) \\ \\ \implies\sf15 \times 18 \\ \\ \implies \sf270 \\ \\\large\underline{ \green{ \sf Area \: of \: quadrilateral = 270 \: {cm}^{2}} }$

Answer 2

Step-by-step explanation:

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