the diagonal of a quadrilateral is 48cm in length and the length of a perpendicular to it from the opposite vertices is 126 sq. CM and it's base is 18 CM. find its altitude.
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Answer:
=d=48
=h1 =4.8cm
=h2=8.6cm
area of the quadrilater =(h1+h2)/d/2
=(4.8+8.6)/48/2
=13.4×24
=321.6
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