The diagonal of a quadrilateral PQRS are equal and meet at 0. The oppositi sides of the quadrilateral are equal. If SPR=50,find
1.= PSO
2.=POS
3.=QSR
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we know that in rhombus and square all sides are 90°
so angle SPR =50°
then angle R = 50°( by alternate formula)
then, angle PSO = 50°and angle PSO half will be 40°(because in square all sodes are 90°)
then, angle Q half will be 40° also ( alternate formula)
angle POS = 40°+40°=80°
angle R = 40°
so, angle PSO = 50°
angle POS = 80°
angle QSR = 40°
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