Question

the diagonal of a quadrilateral shape field is 24 and the perpendicular dropped on it from the remaining opposite vertex are 8 metre and 13 metre find the area of the field ​

Answer 1

Step-by-step explanation:

Area of 1st triangle = 1/2 * base * height

= 1/2 *24*8

=96 m square

Area of 2 nd triangle 1/2 * base * height

=52 m square

now simply add

Answer 2

$\huge \boxed{ \fcolorbox{cyan}{pink}{Answer : }}$

$\sf{area \: of \: a \: quadrilateral}$

________________________________

$\sf{so}$

$\sf{ \frac{1}{2} \times diagonal \times \: sum \: of \: perpendicular}$

$\sf{on \: the \: diagonal \: from \: opp \: sides}$

$\rm{ \frac{1}{2} \times 24 \times (8 + {13)m}^{2}}$

$\rm{ \frac{1}{2} \times 24 \times {21m}^{2}}$

$\rm{12 \times 21 {m}^{2}}$

$\rm{252 {m}^{2}}$

so Answer is 252