the diagonal of a quadrilateral shaped field in 24 mand the perpendicular dropped on it remaining opposite verticals are 11 in a 13 will area of the field? solve in full state mate
Answers
Given:
✰ The diagonal of a quadrilateral shaped field = 24 m
✰ The perpendiculars dropped on its remaining opposite verticals are 11 and 13.
To find:
✠ Area of the quadrilateral shaped field.
Solution:
Let's understand the concept first! First we will construct a quadrilateral ABCD and draw a diagonal BD, which divides the quadrilateral into two parts, then we will draw perpendicular from its vertex A i.e, AM and another perpendicular from its vertex C i.e, CN. After that we will find the area of triangle ABD and triangle BCD respectively by using of area of triangle. Putting the values in the formula and then doing the required calculations After that we will add the area of triangle ABD and BCD to find the area of the quadrilateral shaped field.
Let's find out...✧
Let ABCD be the quadrilateral shaped field and BD is the diagonal which divides the quadrilateral into two parts.
These two parts are triangles.
✭ Area of triangle = 1/2 × base × height ✭
➛ Area of ∆ABD = 1/2 × 24 × 13
➛ Area of ∆ABD = 1/2 × 312
➛ Area of ∆ABD = 312/2
➛ Area of ∆ABD = 156 cm²
Then,
➛ Area of ∆BCD = 1/2 × 24 × 8
➛ Area of ∆BCD = 1/2 × 192
➛ Area of ∆BCD = 192/2
➛ Area of ∆BCD = 96 cm²
Now,
➤ Area of quadrilateral ABCD = Area of ∆ABD + Area of ∆BCD
➤ Area of quadrilateral ABCD = 156 + 96
➤ Area of quadrilateral ABCD = 252 cm²
∴ Area of the quadrilateral shaped field = 252 cm²
_______________________________
Given :
- The diagonal of a quadrilateral shaped field in 24 mand the perpendicular dropped on it remaining opposite verticals are 11 in a 13 will area of the field .
To find :
- Solve in full state .
Formula Used :
= Area of upper triangle + Area of Lower triangle
Solution :
Area of the field
Hence , the full state is 252 sq m