Question

The diagonal of a quadrilateral shaped field is 24 m and the remaining opposite
verticles are 8 m and 13 m. Find the area of the field.

Answer 1

Answer:

Let ABCD be the given quadrilateral in which BE⊥AC and DF⊥AC.

DF⊥AC.It is given that

DF⊥AC.It is given thatAC=24m,BE=8m and DF=13m.

DF=13m.Now, area of quad. ABCD=area of

ΔABC+ area of ΔACD

= 1 × AC × BE + 1 × AC × DF

2. 2

= (12 × 8 + 12 × 13)m²

= (96 + 156)m² =252m²