Question

The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 6 m and 12 m. Find the area of the field. *

2 points

125 sq.m

216 sq.m

432 sq.m

343 sq.m

​

Answer 1

Answer:

Area of the field

= Area of upper triangle + Area of Lower triangle

=21×13×24+21×8×24

=156+96=252 sq m

Answer 2

Answer:

252sq.m

Step-by-step explanation:

Area of the field

= Area of upper triangle + Area of Lower triangle

=  

2

1

​  

×13×24+  

2

1

​  

×8×24

=156+96=252 sq m