Question

The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.​

Answer 1

Answer:

refer the attachment mate

Answer 2

Given:-

• The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m.

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To find:-

• Area of the field.

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Solution:-

☆Area of the field = area of ∆ABD + area of ∆BCD

→ 1/2 × b × h + 1/2 × b × h

→ 1/2 × 24 × 13 + 1/2 × 24 × 8

→ 12 × 13 + 12 × 8

→ 12 × (13 + 8)

→ 12 × 21

→ 252 m²

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Hence,

• the area of the field is 252 m².

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★More to know :-

$\sf{Area\;of\;Rectangle\;=\;Length\;\times\;Breadth}$

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$\sf{Area\;of\;Square\;=\;(Side)^{2}}$

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$\sf{Area\;of\;Triangle\;=\;\dfrac{1}{2}\;\times\;Base\;\times\;Height}$

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$\sf{Area\;of\;Parallelogram\;=\;Base\;\times\;Height}$

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$\sf{Area\;of\;Circle\;=\;\pi r^{2}}$

$\sf{Perimeter\;of\;Rectangle\;=\;2\;\times\;(Length\;+\;Breadth)}$

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$\sf{Perimeter\;of\;Rectangle\;=\;4\;\times\;(Side)}$

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$\sf{Perimeter\;of\;Circle\;=\;2\pi r}$