The diagonal of a quadrilateral shaped field is 24m and perpendiculars dropped
on it from the remaining opposite vertices are 6m and 12m. Find the area of the
field.
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2
Answer:
Area of the field
= Area of upper triangle + Area of Lower triangle
=21×13×24+21×8×24
=156+96=252 sq m
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1
divide the quadrilateral into two triangles from its diagonal
area of 1st triangle=1/2×b×h
=1/2×24×6
=72m²
area of 2nd triangle= 1/2×b×h
=1/2×24×12
=144m²
area of quadrilateral=72+144=216m²
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