Question

The diagonal of a quadrilateral shaped field is 24m and the perpendiculars dropped on it from the remaining opposite vertices are 8m and 13m. Find the area of the field.

Answer 1

13*24/2+24*8/2
=156+96m^2
=252m^2
if we divide the whole figures in 2 triangles

Answer 2

Step-by-step explanation:

$\tiny \bigstar \: \: \underline{ \boxed{\sf Area \: of \: Quadrilateral = \dfrac{1}{2} \times Sum \: of \: the \: perpendiculars \: on \: the \: diagonal \: from \: opposite \: vertices}} \: \: \bigstar$

$: \implies\sf Area \: of \: Quadrilateral = \dfrac{1}{2} \times 24 \times (8 + 13)$

$: \implies\sf Area \: of \: Quadrilateral = \dfrac{1}{ \cancel{2}} \times \cancel{24} \times 21$

$: \implies\sf Area \: of \: Quadrilateral = 12 \times 24$

$: \implies \underline{ \boxed{\sf Area \: of \: Quadrilateral = 252 \: {m}^{2} }} \\ </p><p>$