Question

The diagonal of a quadrilateral-shaped field is 24m and the perpendiculars dropped on it from the remaining opposite vertices are 8m and 13m. Find the area of the field.

Answer 1

Answer:

Step-by-step explanation:

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Answer: Area of Trapezium

`=1/2xx` sum of parallel sides `xx` perpendicular distance

Parallel sides = 1 and 1.2 m

And perpendicular distance = 0.8 m

So, Area `=1/2xx(1+1.2)xx0.8`

`=1.1xx0.8=0.88` sq m

Answer 2

Answer:

252m²

Step-by-step explanation:

Area of quadrilateral =½× (Length of one diagonal) × (Sum of offsets corresponding to the diagonal)

$hence \: area \: of \: field \: = \frac{1}{2} \times 24(8 + 13) \\ = 12 \times 21 = 252 {m}^{2}$