Question

The diagonal of a quadrilateral shaped field is 26 m and the perpendiculars dropped on it from the remaining opposite vertices are 12 m and 5 m. Find the area of the field.

Answer 1

Answer:

Area of the field

= Area of upper triangle + Area of Lower triangle

=

2

1

×13×24+

2

1

×8×24

=156+96=252 sq m

Answer 2

Answer:

Area of the field

= Area of upper triangle + Area of Lower triangle

=

$1 |2\times 13 \times 24 + 1 |2 \times 8 \times 24 \\ \\ = 156 + 96 = 252sq \: \: m$

Hence = 252 sq m