Question

The diagonal of a quadrilateral shaped field is 48 m and the perpendicular dropped on it from the remaining opposite vertices are 16m and 26m. Find the area of the field.

Answer 1

Given:

The diagonal of a quadrilateral shaped field is 48 m and the perpendicular dropped on it from the remaining opposite vertices are 16 m and 26 m

To find:

The area of the field

Solution:

Let's consider,

ABCD as the quadrilateral shaped field

BD is the diagonal of the quadrilateral

AM ⊥ BD is drawn from the vertex A

CN ⊥ BD is drawn from the vertex C

The length of AM = 16 m

The length of CN = 26 m

The length of BD = 48 m

Therefore, referring to the figure, we get

The area of quadrilateral ABCD is,

= Area(Δ ABD) + Area (Δ BCD)

= $[\frac{1}{2} \times AM \times BD] + [\frac{1}{2} \times CN \times BD]$

= $[\frac{1}{2} \times 16 \times 48] + [\frac{1}{2} \times 26 \times 48]$

= $[8 \times 48] + [13 \times 48]$

= $384 + 624$

= $\bold{1008 \:m^2 }$

Thus, the area of the quadrilateral shaped field is → 1008 m².

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Answer 2

Answer:

please anyone help me out with this

Step-by-step explanation:

I have to do maths assignment