The diagonal of a quadrilateral shaped ground is 34 m and the perpendiculars dropped on it from the
remaining opposite vertices are 6 m and 11 m. Find the area of the ground.
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Given : -
The diagonal of a quadrilateral shaped ground is 34 m and the perpendiculars dropped on it from theremaining opposite vertices are 6 m and 11 m. Find the area of the ground.
To Find : -
Area
Answer : -
Here, Diagonal AC = 34 m
Perpendicular DX = 11 m
And, perpendicular BY = 6 m
Therefore, sum of perpendicular = DX + BY = 11+6 m = 17 m
Now, area of quadrilateral = 1/2 × AC × (DX+BY) = 1/2 × 34 m × 17 m = 1 × 17 m × 17 m
= 1 × 289 m
= 289 m
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