the diagonal of a ractangular courtyard is 61m. if the lenght is 60m , find the area of a courtyard ?
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If the diagnal is 61m and the length is 60
There are two triangles in this courtyard. Assume a triangle. The base is 60m, the hypotenuse is 61m, to find the height (width), we have to use the formula a2 + b2 = c2
602 + b2 = 612
b2 = 612 - 602
b2 = 121 ..... ......... ...... .......... ..... .... ........... using a2 - b2 = (a - b) (a + b)
b = 11 .... ........... ........... ........... ........ ....... .. square rooting both sides.
hence the heigh is 11m
The width is 11m
Hence the area is l x b = 60 x 11 = 660m
Hope this helps!!
There are two triangles in this courtyard. Assume a triangle. The base is 60m, the hypotenuse is 61m, to find the height (width), we have to use the formula a2 + b2 = c2
602 + b2 = 612
b2 = 612 - 602
b2 = 121 ..... ......... ...... .......... ..... .... ........... using a2 - b2 = (a - b) (a + b)
b = 11 .... ........... ........... ........... ........ ....... .. square rooting both sides.
hence the heigh is 11m
The width is 11m
Hence the area is l x b = 60 x 11 = 660m
Hope this helps!!
manav39:
thank you
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