the diagonal of a rectangle ABCD interect at o.if angle boc =70degree.find angle oda.
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Angle boc = angle doa ( vertically opposite angles)
OD = OA ( diagonals bisect each other)
So angle oad = angle oda
let these angles be x
then
oad+oda+aod = 180
x+x+70 = 180
2x = 110
x = 55
therefore angle oda and oad = 55
OD = OA ( diagonals bisect each other)
So angle oad = angle oda
let these angles be x
then
oad+oda+aod = 180
x+x+70 = 180
2x = 110
x = 55
therefore angle oda and oad = 55
KJennifer:
thnxx..☺☺
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