the diagonal of a rectangle ABCD intersect at O. if angleBOC = 52 find angle ODA
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In triangle BOC,
ang BOC +ang OCB+ang OBC= 180°
52°+2 ang OBC= 180° [as triangle OBC is an isocelestriangle, the base angles are equal]
2 ang OBC=180°-52°
=128°
ang OBC=128/2 °
ang OBC=64°
ang OBC=ang ODA
ang ODA=64°
Plz make it as BRAINLIEST ANSWER
ang BOC +ang OCB+ang OBC= 180°
52°+2 ang OBC= 180° [as triangle OBC is an isocelestriangle, the base angles are equal]
2 ang OBC=180°-52°
=128°
ang OBC=128/2 °
ang OBC=64°
ang OBC=ang ODA
ang ODA=64°
Plz make it as BRAINLIEST ANSWER
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