Question

The diagonal of a rectangle ABCD intersect at the point O . If ∠BOC = 50°, then find∠OAD.​

Answer 1

Answer:

Given angle BOC = 50°

and angle AOD = BOC ...( vertically opposite angles)

now, in ∆AOD , since AO = OD ...( diagonal bisector)

so, angle ODA = OAD , let say x .

now adding all angles we get

x+x + 50° = 180°

=> 2x = 180°-50° = 130°

=>x = 130°/2 = 65°

which means angle ODA = 65°

Answer 2

65°

Step-by-step explanation:

Given angle BOC = 50°

and angle AOD = BOC ...( vertically opposite angles)

now, in ∆AOD , since AO = OD ...( diagonal bisector)

so, angle ODA = OAD , let say x .

now adding all angles we get

x+x + 50° = 180°

=> 2x = 180°-50° = 130°

=>x = 130°/2 = 65°

which means angle ODA = 65°