Question

The diagonal of a rectangle field is 60 m more than the shorter side. if the longer side is 30 metres more than the shorter side, find the side of the field

Answer 1

Let shorter side =x. Diagonal=x+60. Longer side =x+30. in rectangle , each angle is 90°. by Applying Pythagoras thm:( x+60)^2=(x+30)^2+x^2. now please solve.

Answer 2

Given:-

Long side of rectangular field is 60 meters more then the shorter side.

Let the longer side will be (y+30)mtr.

And the length of the diagonal will be (y+60) mtr.

Solution:-

Using Pythagoras theorem,

(Diagonal)² = (shorter side)² + (longer side)²

⇒(y+60)² = y² + (y+30)²

⇒y² + 3600 + 120y = y² + y²+900+60y

⇒3600+120y−y² −900−60y = 0

⇒−y² +60y+2700=0

⇒y² −60y−2700=0

⇒y² −(90−30)y−2700=0

⇒y² −90y+30y−2700=0

⇒y(y−90)+30(y−90)=0

⇒(y−90)(y+30)=0

If,

y+30=0

⇒ y=−30 (not possible)

If,

y−90=0

⇒y=90

So, the length of shorter side = y

So, the length of shorter side = y =60

Longer side 90+30=120

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