Question

The diagonal of a rectangle has the length 10 m and its length is twice its width find it area​ ??

Answer 1

Step-by-step explanation:

Here, let width= x

length= 2x

diagonal= √(l²+w²)

10m=√(2x)²+(x)²

10m=√4x²+x²

10m=√5x²

x= 10m/√5 =(2√5)m

width= (2√5)m

length= 2× 2√5 m= 4✓5 m

area= l×w

= 2✓5 m × 4√5 m

= 8×5m² = 40m²