Question

the Diagonal of a rectangle is
10 m and its breadth is 6 cm. find its :
length and area​

Answer 1

Step-by-step explanation:

$digonal \: of \: rectangle = \sqrt{l { }^{2} + b {}^{2} }$

$10 = \sqrt{l {}^{2} + 36 }$

$100 = l { }^{2} + 36$

$l {}^{2} = 100 - 36$

$l = \sqrt{64}$

l=8

Answer 2

Step-by-step explanation:

Diagonal of rectangle^2 = length ^2 + breadth ^2

10^2= length ^2+ 6^2

100 = length ^ 2 + 36

Length ^2 = 100-36

=64

Length = the square root of 64

Length = 8m answer

Area = length x breadth

= 8 x 6

=48m