Question

The diagonal of a rectangle is 10cm and its breadth is 6cm find it 1) length. 2) area


answer please

step by step
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Answer 1

${\bold{\rm{ \color{purple}{ QueStioN\: }}}}$

The diagonal of a rectangle is 10cm and its breadth is 6cm . Then find its length.

${\bold{\rm{ \color{purple}{ Answer \: }}}}$

$length = \sqrt{(diognal) {}^{2} - (breadth) {}^{2} }$

$l = \sqrt{(10) {}^{2} - (6) {}^{2} }$

$\sqrt{100 - 36} = \sqrt{64} = 8cm$

Required length is 8 cm

${\bold{\rm{ \color{purple}{ Question \: }}}}$

The diagonal of a rectangle is 10cm and its breadth is 6cm . Then find its area .

${\bold{\rm{ \color{purple}{ Answer \: }}}}$

$area = length \times breadth$

$a = 8 \times 6$

$a = 48 {cm}^{2}$

Required area is 48 cm²

Answer 2

$\huge\bold{\mid{\boxed{\sf{\color{pink}{Question}}}}\mid}$

The diagonal of a rectangle is 10cm and its breadth is 6cm . Then find its length ?

$\huge\bold{\mid{\boxed{\sf{\color{pink}{Answer}}}}\mid}$

$length = \sqrt{(diognal) {}^{2} - (breadth) {}^{2} }$

$l = \sqrt{(10) {}^{2} - () {6}^{2} }$

$\sqrt{100 - 36}$

$= \sqrt{64} = 8cm$

Required length is 8 cm

$\huge\bold{\mid{\boxed{\sf{\color{pink}{Question}}}}\mid}$

The diagonal of a rectangle is 10cm and its breadth is 6cm . Then find its area ??

$\huge\bold{\mid{\boxed{\sf{\color{pink}{Answer}}}}\mid}$

$area = length \times breadth$

$a = 8 \times 6$

$a = 48cm {}^{2}$

Required area is 48 cm²

${\bold{\rm{ \color{purple}{ @Shardabante1234 \: }}}}$