Question

The diagonal of a rectangle is 34 cm. If its breadth is 16 cm; find its : (i) length (ii) area​

Answer 1

Answer:

length hoga

Step-by-step explanation:

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Answer 2

AC2 = AB2+BC2 (By Pythagoras theorem)

AC2 = AB2+BC2 (By Pythagoras theorem)(34)2 = l2 + (16)2

AC2 = AB2+BC2 (By Pythagoras theorem)(34)2 = l2 + (16)2 1156 = l2 + 256

AC2 = AB2+BC2 (By Pythagoras theorem)(34)2 = l2 + (16)2 1156 = l2 + 256l2 = 1156 – 256

AC2 = AB2+BC2 (By Pythagoras theorem)(34)2 = l2 + (16)2 1156 = l2 + 256l2 = 1156 – 256l2 = 900

AC2 = AB2+BC2 (By Pythagoras theorem)(34)2 = l2 + (16)2 1156 = l2 + 256l2 = 1156 – 256l2 = 900l = √900 = 30 cm

AC2 = AB2+BC2 (By Pythagoras theorem)(34)2 = l2 + (16)2 1156 = l2 + 256l2 = 1156 – 256l2 = 900l = √900 = 30 cmarea = l x b = 30 x 16 = 480 cm2

AC2 = AB2+BC2 (By Pythagoras theorem)(34)2 = l2 + (16)2 1156 = l2 + 256l2 = 1156 – 256l2 = 900l = √900 = 30 cmarea = l x b = 30 x 16 = 480 cm2 (i) 30 cm (ii) 480 cm2

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