The diagonal of a rectangle is 36cm.If it's breadth is 16cm;find its length and area
Answers
a square+b square=36×36
a^2+16×16=36×36
a^2+256=1296
a^2=1040
a=32.2cm
length=32.2cm
breadth=16 cm
area=32.2×16
area=515.2
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Question:-
The diagonal of a rectangle is 36cm.If it's breadth is 16cm;find its length and area
Solution:-
Given:-
1. breadth of rectangle are 16 cm and diagonal is of 36 cm respectively.
let, AD = BC = 16 cm and
AC = BD = 36 cm.
Find:-
1. Area of rectangle.
we know
The property of rectangle:-
1. interior angles of rectangle are of 90°.
2. opposite side of rectangle are equal.
3. diagonals of rectangle bisect each other at 90°.
4. both diagonals of rectangle are equal.
So now
To find length of side
we use Pythagoras theorem.
=> (AC)² = (AB)² + (BC)²
=> (36)² = (AB)² + (16)²
=> 1296 = (AB)² + 256
=> (AB)²= 1296 -256
=> (AB)² = 1040
=> AB = √1040 = √16×65
=> AB= 4√65 cm.
so AB = CD= 4√65 cm.
we know formula for
=> Area of rectangle
= length× breadth
=> Area of rectangle = (AB) × ( BC)
=> Area of rectangle = 4√65 × 16
=> Area of rectangle = 64√65 cm²
Hence area of rectangle
64√65 cm².
i hope it helps you.