Question

The diagonal of a rectangle is 60 m more than its shorter side and the larger side is 30 m more than the shorter side.

Answer 1

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Its weong or right

Answer 2

Let’s consider the shorter side of the rectangle to be x m.

Then, the length of the other side = (x + 30) m

Length of the diagonal = (x + 60) m

By using Pythagoras theorem,

(x + 60)2 = x2 + (x + 30)2

x2 + 3600 + 120x = x2 + x2 + 900 + 60x

x2 – 60x – 2700 = 0x2 – 90x + 30x – 2700 = 0

x(x – 90) + 30(x – 90) = 0

(x – 90) (x + 30) = 0

x = 90, -30

As, x cannot be negative. Hence, x = 90 is only valid.

Therefore, the sides of the rectangle are 90 m and (90 + 30) m = 120 m.