The diagonal of a rectangular field is 16 meters more than the shorter side. If the longer side is 14 meters more than the shorter side, then find the lengths of the sies of the field.
Answers
Answered by
1
(16+x)^2=(14+x)^2+x^2
256+32x+x^2=196+28x+x^2+x^2
60+4x-x^2=0
60+10x-6x-x^2=0
10(6+x)-x(6+x)=0
(6+x)(10-x)=0
x=-6
x=10
shorter side is 10
longer side is 24
256+32x+x^2=196+28x+x^2+x^2
60+4x-x^2=0
60+10x-6x-x^2=0
10(6+x)-x(6+x)=0
(6+x)(10-x)=0
x=-6
x=10
shorter side is 10
longer side is 24
Similar questions