Question

the diagonal of a rectangular field is 28 more than the shorter side and the longer side is 14 more then the shorter side. find the lengths of the sides of the rectangular field.

Answer 1

hooo user the shortest side =x ,. then longer side =14+x. diagnol side =28+x ,by applying pythogoas theorem ,diagnol side^2=longer side ^2+shortest side^2

Answer 2

The sides of the rectangle are :-
$42cm \: and \: 56cm$



Please refer the above photograph for the used process.




KEY POINTS TO REMEMBER :-


☸️ MIDDLE TERM SPLITTING
In this process the given equation is factorized by splitting the middle term of the equation
(refer to the last step of the attachment)


☸️ PROPERTIES OF RECTANGLE :-


♗The diagonals of a rectangle are equal and bisect each other.

♗opposite sides of a rectangle are parallel.

♗opposite sides of a rectangle are congruent.

♗opposite angles of a rectangle are congruent.

♗All four angles of a rectangle are right angles.

♗The diagonals of a rectangle are congruent.


☸️ PYTHAGORAS THEOREM
The theorem is only applicable in right angled triangles. It states that :-

H² = P² + B²



Thanks!