The diagonal of a rectangular field is 60m more than the shorter side. Find the sides of the field.
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Let the length of the shorter side be x metres.
The length of the diagonal= 60+x metres
The length of the longer side =30+x metres
Applying Pythagoras theorem,
Diagonal²=longer side²+shorter side²
(60+x) ²= (30+x) ² + x²
3600+120x+x²=900+60x+x²+x²
2700+60x-x²=0
2700+90x-30x-x²=0
90(30+x)-x(30+x) =0
X=90,
Shorter side is 90m, longer side is 90+30=120m
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