the diagonal of a rectangular solid is is 5√2dm if the length and width are 5dm,4dm then find its height.
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The dimensions i.e. length, breadth and height of the rectangular box are 5, 4 and h. I am giving notation for root as R and square as S. While taking note of this solution replace R with root symbol and S with square symbol.
The length of base diagonal is R(5S+4S) = R(25+16) = R(41)
Now calculating the major diagonal, the two sides (of right angled triangle) will be height (h) and base diagonal (R41). It is R(R41S+hS) = 5R2.
Squaring on both sides 41+hS=25*2.
hS=50-41
hS=9
h=3
So the height of rectangular box is 3.
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height =9
here is ur answer
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