The diagonal of a rhombus ABCD intersect at 0.If AC = 40cm and BD = 42cm,find the length of the side of rhombus
Answers
- As per the properties of the rhombus, it's diagonals bisect each other at a angle of 90° .
- As the diagonals bisect each other, so the diagonals are divided into two equal parts .
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↦ As the diagonals are divided into two equal parts
- So ,
- AO = 1/2 × 40 = 20 cm
- BO = 1/2 × 42 = 21 cm
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➜ In ∆ AOB
- ∠ AOB = 90° ..... ( As per the properties of the rhombus )
↦ So ∆ AOB is a Right Angled Triangle .
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↦ Taking Square Root on both the side's :-
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∴ The side of the Rhombus is 29 cm
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↦ What is a Rhombus :-
➛ Rhombus is a special case of a parallelogram, and it is a four-sided quadrilateral. In a rhombus, opposite sides are parallel and the opposite angles are equal. Moreover, all the sides of a rhombus are equal in length, and the diagonals bisect each other at right angles. The rhombus is also called a diamond or rhombus diamond.
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↦Properties of the Rhombus :-
- All sides of the rhombus are equal.
- The opposite sides of a rhombus are parallel.
- Opposite angles of a rhombus are equal.
- In a rhombus, diagonals bisect each other at right angles.
- Diagonals bisect the angles of a rhombus.
- The sum of two adjacent angles is equal to 180 degrees.
- The two diagonals of a rhombus form four right-angled triangles which are congruent to each other.
- You will get a rectangle when you join the midpoint of the sides.
- You will get another rhombus when you join the midpoints of half the diagonal.
- Around a rhombus, there can be no circumscribing circle.
- Within a rhombus, there can be no inscribing circle.
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