Question

THE DIAGONAL OF A RHOMBUS ARE 12CM AND 16CM. FIND THE AREAS AND ALSO THE LENGTH OF THE SIDE OF THE RHOMBUS

Answer 1

area = half of d1 × d2
= half of 12 × 16
= half of 192 = 96 cm2
using Pythagoras theorem in trinagle POS

side^2 = ( 12/2) ^2 + (16/2)^2
= 6^2 + 8^2
side^2 = 36 + 64 = 100

side = square root of 100
= 10 cm

Answer 2

Question:-

The lengths of the diagonals of a rhombus are 16cm and 12cm. then find the length of the side of rhombus

Solution:-

we know that diagonal of rhombus,bisect each other in right angle ( 90° ).

we also know that all sides of rhombus are equal ( of equal length ).

so, now

Let rhombus is ABCD and

Diagonal of rhombus are

BD = 16 cm and AC = 12 cm

means,

OD = 8 cm and AO = 6 cm

By pythagorus theorem

To find length of AD ( and all side of rhombus )

=> (AD)² = (OD)² + (AO)²

=> (AD)² = (8)² + (6)²

=> (AD)² = 64 + 36

=> (AD)² = 100

=> AD = √100

=> AD = 10 cm

=>Area of rhombus

=(product of diagonal)/2

=>Area of rhombus = (16×12)/2

=>Area of rhombus = 192/2

=>Area of rhombus = 96 cm²

Hence length of all side

of rhombus is 10 cm and

is Area of rhombus is

96 cm².

i hope it helps you.