Math, asked by kamarulkaba, 7 months ago

the diagonal of a rhombus are 15 cm and 20 cm.Find its area and perimeter?​

Answers

Answered by madhu2802
9

Step-by-step explanation:

Area of rhombus = product of diagonals /2

Area =15*20/2

Area =150cm²

The diagonals of rhombus bisects eac h other by 90°

Then by Pythagoras theorem,

(15/2)²+(20/2)²=side²

225/4 +100=side²

(225+400)/100=side²

625=100side²

625=(10side)²

√625 =side

25 =side

Perimeter =4*25

Perimeter =100cm

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Answered by vaishu21n
1

Answer: Step-by-step explanation: Area of rhombus = product of diagonals /2

Area =15*20/2

Area =150cm²

The diagonals of rhombus bisects eac h other by 90°

Then by Pythagoras theorem,

[15/2)²+(20/2)²=side²

225/4 +100=side²

(225+400)/100=side²

625=100side²

625=(10side)² √625 =side

25 =side

Perimeter =4*25

Perimeter =100cm

[please mark as brilliant]

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