the diagonal of a rhombus are 15 cm and 20 cm.Find its area and perimeter?
Answers
Answered by
9
Step-by-step explanation:
Area of rhombus = product of diagonals /2
Area =15*20/2
Area =150cm²
The diagonals of rhombus bisects eac h other by 90°
Then by Pythagoras theorem,
(15/2)²+(20/2)²=side²
225/4 +100=side²
(225+400)/100=side²
625=100side²
625=(10side)²
√625 =side
25 =side
Perimeter =4*25
Perimeter =100cm
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Answered by
1
Answer: Step-by-step explanation: Area of rhombus = product of diagonals /2
Area =15*20/2
Area =150cm²
The diagonals of rhombus bisects eac h other by 90°
Then by Pythagoras theorem,
[15/2)²+(20/2)²=side²
225/4 +100=side²
(225+400)/100=side²
625=100side²
625=(10side)² √625 =side
25 =side
Perimeter =4*25
Perimeter =100cm
[please mark as brilliant]
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