Question

the diagonal of a rhombus are 16 cm and 12 cm long find its perimeter​

Answer 1

Answer

Diagonal of a rhombus=16 and 12

Perimeter of rhombus= 4*16+12

=4*30

=120 cm

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Step-by-step explanation:

Answer 2

Answer:

$\boxed{40 cm}$  

Step-by-step explanation:

Given:

Diagonals of the Rhombus = 12cm and 16cm

To find:

Perimeter of the Rhombus. = ?

For Information:

• In a rhombus, diagonals bisect each other at right angles.

• All sides of the rhombus are equal.

• The sum of two adjacent angles is equal to 180 degrees

Solution:

FROM THE FIGURE,

$AC^{2} = AB^{2} + BC^{2}$

⇒$AC^{2} = 8^{2} + 6^{2}$

⇒$AC^{2} = 64 + 36$

⇒$AC^{2} = 100$

⇒$AC= \sqrt{100}$

⇒AC = 10cm

∴The lengths of side  of the Rhombus =$\boxed{10 cm}$

Perimeter of Rhombus = 4 × Side

                                   = 4 × 10cm

                                   = $\boxed{40 cm}$  

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https://brainly.in/question/25057517

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