Question

the diagonal of a rhombus are 16m and 12m find its length of its side​

Answer 1

Step-by-step explanation:

we have sides of the rhombus d1= 16 cm and d2 = 12 cm

So to find side of rhombus s = (√d1^2 + d2 ^2) / 2

= (√ 16^2 + 12^2) /2

= (√256+144)/2

= √400/2

=20/2

= 10 cm

Answer 2

Answer:

suppose ABCD is a rhombus Diagonal AC=16cm and BD=12cm

Now, we have to find the side of rhombus

In rhombus Diagonal AC And BD intersect at O , and bisects each other at 90°.

so, we have

AO=OC. (Diagonal bisect each other in equal part)

AC=AO+CO

AC=16cm (given)

16cm=OA+OA

2OA=16cm

OA=16/2

OA=8cm

similarly OB =6cm

Now in Triangle AOB

OA=8cm, OB=6cm

OA =Base , OB =Perpendicular

AB=hypotenus

Hypotenus=√perpendicular square +base square

AB=√OAsquare+OB square

AB=√8^2+6^2

AB=√64+36

AB=√100

AB=10cm

similarly AB=BC=CD=DA (side of a rhombus are equal)

so side of a rhombus is 10 cm.

i hope it will help you