The diagonal of a rhombus are 18 cm and 24 cm.find; it's area, length of its sides and it's perimeter.
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hey
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•diagonals of rhombus bisect each other at right angle
•area of rhombus=1/2*d1*d2
•perimeter of rhombus=4*side
now using phythagoras theorem
(AB)^2 =(AO)^2+(OB)^2
(AB)^2=(12)^2+(9)^2
AB=√144+81
AB=√225
AB=15cm
•all sides of rhombus are equal
AB=BC=CD=AD=15cm
•perimeter=4*15=60cm
•area=1/2*18*24=216cm^2
hope helped
_______________
_______
•diagonals of rhombus bisect each other at right angle
•area of rhombus=1/2*d1*d2
•perimeter of rhombus=4*side
now using phythagoras theorem
(AB)^2 =(AO)^2+(OB)^2
(AB)^2=(12)^2+(9)^2
AB=√144+81
AB=√225
AB=15cm
•all sides of rhombus are equal
AB=BC=CD=AD=15cm
•perimeter=4*15=60cm
•area=1/2*18*24=216cm^2
hope helped
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palram4517:
Thanx you soooooooooo much
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