Question

The diagonal of a rhombus are 24 cm and 10 cm.the perimeter of the rhombus is

Answer 1

Hi , there !!!


d1 = 24


D1 / 2 = length of half of diagonal

=> 24 / 2

= > 12 cm


similarly

10 / 2 = 5


now ,

AB² = AO² + OB ²

AB ²= 12² + 5²

AB² = 169

AB = 13 cm


now , perimeter = 4 × side

13 × 4 cm.

=> 52cm


hope it helps !!

thanks

Ranjan Kumar

Answer 2

$here \: is \: your \: answer$


the diagonal of a rhombus are 24 cm and 10 cm.

↪we know that diagonals of the rhombus || bisectors.

To find the side of rhombus ,

using the pythagorean theorm ,

${x}^{2} = {12}^{2} + {5}^{2}$


$= 144 + 25 = 169 \: \: < = > x = \sqrt{169}$

x = 13 cm.

sides of rhombus is equal to it's perimeter ,

4 ×13 = 52.cm is the answer .

$hope \: it \: helps$


$\beta e \: \beta \gamma \alpha inly$