Question

the diagonal of a rhombus are 24 cm and 32 cm find the sum of those two number​

Answer 1

Answer:

56

Step-by-step explanation:

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Answer 2

Answer:

Every rhombus is cut into (4) congruënt right triangles.

Every rhombus is cut into (4) congruënt right triangles.The "legs" of each one will be half of 24cm and half of 32cm: that is, 12cm and 16cm. The Pythagorean Theorem says that the remaining side, the hypotenuse, will be √(12^2+16^2)cm; 12^2+16^2=144+256=400; √400=20. That gives us one side of the rhombus at 20cm.

Every rhombus is cut into (4) congruënt right triangles.The "legs" of each one will be half of 24cm and half of 32cm: that is, 12cm and 16cm. The Pythagorean Theorem says that the remaining side, the hypotenuse, will be √(12^2+16^2)cm; 12^2+16^2=144+256=400; √400=20. That gives us one side of the rhombus at 20cm.The entire rhombus has (4) of these, so our perimeter is 4×20cm=80cm.

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