Question

the diagonal of a rhombus are 6 cm and 8 cm respectively. find the perimeter of this rhombus.​

Answer 1

Answer:

Since the diagonals of a rhombus intersect at a right angle, and each of the 4 sides are equal, the diagonals intersect at their midpoints. That means drawing the diagonals on the rhombus split it into 4 smaller right triangles. Each right triangle has side lengths 3 and 4, (half the length of the diagonals). By Pythagoras, each side length of the rhombus is 5. Therefore the perimeter is 20.

Answer 2

Given :-

diagonal of rhombus = 6cm

second diagonal = 8cm

perimeter = ?

we will use Pythagoras theorem

AC² = AB² + BC²

AC² = 6² +8²

AC² = 36 +64

AC² = 100

AC =√100

AC = 10 cm

perimeter of rhombus = 4* side

but it's half of diagonal

perimeter = 2*10 = 20cm