Question

the diagonal of a rhombus are 6cm and 8cm.find the length of a side of the rhombus

Answer 1

i hope it will help u

Answer 2

$\huge{\pink{\underline{\star\: Solution\: \star}}}$

For diagram refer attachment:

$Given \colon ABCD \:is \:a rhombus\: whose\: \\diagonal\: AC = 6cm \:and\:BD = 8cm$

Solution :

Statement : Diagonal's of Rhombus bisect each other at O and these are perpendicular .

Now , we have

$AO = \frac{1}{2}\times AC \\ = \frac{1}{2}\times 6 \\= 3\: cm$

$BO = \frac{1}{2}\times BD \\ = \frac{1}{2}\times 8 \\= 4\: cm$

In ∆ AOB

$AB^{2} = AO^{2} + BO^{2}\\\implies 3^{2}+4^{2}\\\implies \sqrt{9+16}\\\implies \sqrt{25}\\\implies 5\: cm$

$\red{\underline{Answer}}$

Statement : Side of Rhombus are always equal.

$\green{\bold{\boxed {AB = BC = CD = DA = 5\:cm}}}$