Question

The diagonal of a rhombus are in the ratio 3 ratio 4 and the area is 54 find the side of the Rhombus

Answer 1

Answer:

Let one diagonal = 3X, then other diagonal will be= 4X

Area of Rhombus = d1*d2/2 = 54 cm2 (given)

or 3X * 4X /2= 54 cm2

or 6 X2 =54cm2

or X = Sqrt (54/6) =3 cm

Therefore d1 = 9 d2 =12

As diagonals are perpendicular bisector of each other

Side of a rhombus = Sqrt { (d1/2)2+(d2/2)2}

side of rhombus = sqrt{(9/2)2+(12/2)2} = Sqrt ( 81/4 + 144/4)= Sqrt(225/4)

or Side = 15 / 2 = 7.5 cm (Ans)