Math, asked by krishnamahakud273, 4 months ago

the diagonal of a rhombus bisect each other at right angle use this fact to find the area of a rhombus whose diagonals are of length 8cm and 6cm​

Answers

Answered by p2286
1

Answer:

1/2*8*6=1/2*48=24cm^2

Step-by-step explanation:

Area of rhombus=1/2*diagnol 1* diagnol 2=1/2*6*8=1/2*48=24cm^2

Answered by ashokshivhare
0

 \frac{1}{2}  \times 8 \times 6  =  \frac{1}{2}  \times 48 = 24cm /\2

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