the diagonal of a rhombus bisect each other at right angles use this fact to find the area of the rhombus whose diagonals are of length 8 and 6 CM
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let AC=8cm and DB=6cm
in rhombus diagonals bisect each other at 90°
therefore ,BO=1/2DB=1/2*6=3cm
AO=1/2AC=1/2*8=4cm
Now, in ΔAOB, angle AOB =90°
:. AB²=AO²+BO²
AB²=4²+3²=16+9=25
AB=√25=5cm
You can find the side of rhombus this way and for the area of rhombus use Area =(d1*d2)÷2
in rhombus diagonals bisect each other at 90°
therefore ,BO=1/2DB=1/2*6=3cm
AO=1/2AC=1/2*8=4cm
Now, in ΔAOB, angle AOB =90°
:. AB²=AO²+BO²
AB²=4²+3²=16+9=25
AB=√25=5cm
You can find the side of rhombus this way and for the area of rhombus use Area =(d1*d2)÷2
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