Question

the diagonal of a rhombus is 16 cm and 30 cm . find its perimeter ?​

Answer 1

Answer:

Given: Diagonals AC=30cm and DB=16cm.

Since the diagonals of the rhombus bisect at right angle to each other.

Therefore,

OD= DB/2=16/2 =8cm

and OC=AC/2=30/2 =15cm

Now, In right angle triangle DOC,

(DC)² =(OD) ²+(CO) ²

⇒(DC) ²=(8) ²+(15) ²

⇒(DC) ²=64+225=289

⇒DC= √289

=17cm

Perimeter of the rhombus=4× side

=4×17=68cm

Thus, the perimeter of rhombus is 68 cm.

I hope it help you..

Answer 2

Answer:

given,the measures of diagonals16,30

We know that diagonals of rhombus are perpendicular bisectors of each other.

Step-by-step explanation:

db=16

DO=DB/2

DO=16/2

DO=8cm

similarly,AO=15cm

by using pythogaras theorem,

DO²+AO²=DA²

8²+15²=DA²

64+225=DA²

289=DA²

DA=17

perimeter=DA×4

             =17×4

PEIMETER=68CM

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