Question

the diagonal of a rhombus is 20 cm and 21 cm find the lenght of its side?​

Answer 1

hello,

we know that in a rhombus the diagonals bisect each other at 90

so let AC=20 AND BD=21 CM

AD=10 AND BO=10.5 CM



AB^2=AD^2+OB^2

=10^2+10.5^2

=100+110.25

=210.25

AB=14.5 IS THE SIDE OF THE RHOMBUS

PRIMETER=4S

=4(14.5)

=58 CM

Answer 2

Answer:

Step-by-step explanation:

We know that in a rhombus the diagonals bisect each other at 90

so let AC=20 AND BD=21 CM

AD=10 AND BO=10.5 CM

AB^2=AD^2+OB^2

=10^2+10.5^2

=100+110.25

=210.25

AB=14.5 IS THE SIDE OF THE RHOMBUS

PRIMETER=4S

=4(14.5)

=58 CM