the diagonal of a rhombus measure 10cm and 24cm . Find it's perimeter .
( Hint : Diagonals of a rhombus bisect each other at right angles)
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Answer:
52 cm
Step-by-step explanation:
Length of the base = 10/2 = 5cm
Length of the height = 24/2 = 12cm
Hypotenuse^2 = side^2+ side^2
Hypotenuse^2= 5^2+ 12^2
Hypotenuse^2 = 25 + 144
Hypotenuse^2 = 169
On taking square root we get,
Hypotenuse = 13 { 13 X 13=169 => √169=13}
Hence the side of the rhombus is 13cm.
Perimeter of the rhombus = 4×side
= 4 × 13
= 52cm.
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